[pmwiki-users] Cookbook path
5ko at free.fr
Sun Feb 10 18:10:56 CST 2008
> I'm writing a Cookbook (or Recipe, I never know which is which), and I
> need to get the URL of the location that the script is executing from --
> basically the cookbook directory. This way gets me the script *path*
> (not the URL), which isn't quite what I need:
> The best I have so far is this (extracted from pmwiki.php), but that
> assumes the location of cookbook directory.
> preg_replace('#/[^/]*$#', '/cookbook', $ScriptUrl, 1)
In most installations, the /cookbook/ directory is read-protected:
cannot and should not be accessed from the internet. It is a security
risk to have this directory world-readable. I believe even PmWiki places
there a .htaccess file denying the access.
Should you access your script from the url, try to use a $HandleActions
$HandleActions['foo'] = 'MyFooFunction';
function MyFooFunction($pagename, $auth="admin")
$page = RetrieveAuthPage($pagename,$auth,1, READPAGE_CURRENT);
# here your code
Now, if you call your page with: http://site/pmwiki.php?action=foo
then the function MyFooFunction() will be executed.
You can see how some other existing recipes do this.
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